please help me with these questions, time sensitivei would offer more points but i only have 35 im sorryplease try to be accurate too if you can, i really need to get this right, but i cant do quadratic functions at allagain, im really sorry that i can only offer 35 points

Answer:1. f(x)=−(x−3)(x+1) By multiplying the factors, the general form is f(x)= -x²+2x+3.Use the formula to find the vertex = (-b/2a, f(-b/2a)) , here in the above equation a=-1(As, a<0 the parabola is open downward), b=2. by putting the values.-b/2a = -2/2(-1) = 1f(-b/2a)= f(1)=-(1)²+2(1)+3= 4So, Vertex = (1, 4)Now, find y- intercept put x=0 in the above equation. f(0)= 0+0+3, we get point (0, 3).Now find x-intercept put y=0 in the above equation. 0= -x²+2x+3.-x²+2x+3=0 the factor form is already given in the question so, ⇒-(x-3)(x+1)=0 ⇒x=3 , x=-1From vertex, y-intercept and x-intercept you can easily plot the graph of given parabolic equation. The graph is attached below.