An FM radio station broadcasts at 98 MHz. what is the energy of each photon in Joule? Use h= 6.6 X10^-34 J*s for Planck constant.
Accepted Solution
A:
Answer:The energy of each photon is [tex]6.468 \times 10^{-26}[/tex] Joule.Step-by-step explanation:Consider the provided information.According to the plank equation:[tex]E=h\nu[/tex]Where E is the energy of photon, h is the plank constant and [tex]\nu[/tex] is the frequency.It is given that [tex]h= 6.6 \times10^{-34}[/tex] and [tex]\nu=98MHz[/tex]98Mhz = [tex]98\times 10^6Hz[/tex]Substitute the respective value in plank equation.[tex]E=6.6\times 10^{-34}\times 98\times 10^6[/tex][tex]E=6.6\times 98\times 10^{-34+6}[/tex][tex]E=646.8 \times10^{-28}[/tex][tex]E=6.468 \times 10^{-26}[/tex]Hence, the energy of each photon is [tex]6.468 \times 10^{-26}[/tex] Joule.