MATH SOLVE

3 months ago

Q:
# g is constructing a triangular sail for a sailboat. Aluminum supports will run along the horizontal base and vertical height of the sail, respectively. After making some measurements, Calculo determines that the height of the sail cannot exceed 12 feet, or else it will not be able to fit under the bridges in the area. In addition, the total weight of the supports cannot exceed 80 pounds, or else the boat will sink. If aluminum weighs 5 pounds per foot, what is the area of the largest sail Calculo can build? Fully justify your answer, doing each step you learned in the class prep. In particular, you must show that the area you found is indeed the largest possible.

Accepted Solution

A:

Answer: A (max) = 1/2 ( 8 * 8 ) = 32 ft²Step-by-step explanation: We have two constrains a) The height of the sail ( support) cannot exceed 12 feetb) The total weight of the supports cannot exceed 80 poundsThe weight of a foot of aluminum is 5 . If we call:x lenght of base support, y height of the vertical support and the sail shape (is a triangle) we haveA = 1/2* ( x + y ) We know that (given a constant perimeter rectangle, the maximun area is the squareA = x * y P = 2x +2y y = (P - 2x ) ÷ 2 A = x * ( P - 2x ) ÷ 2 ⇒ A = (Px -2x²) ÷ 2if we get derivative A´(x) = (P-4x)/2 ⇒ (P-4x)/2 = 0P = 4x and x = P/4Now we can look an square as two straight triangles joined by the diagonal and these two triangles are of area maximun.Therefore in our case the sail must be of 8 x 8 feet (base and height)A (max) = 1/2 ( 8 * 8 ) = 32 ft² and we will keep the condition of weigh8 + 8 = 16 feet and the supports weights 16 * 5 = 80 pounds